20y^2=90

Solution for 20y^2=90 equation:

20y^2=90

We move all terms to the left:

20y^2-(90)=0

a = 20; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·20·(-90)
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{2}}{2*20}=\frac{0-60\sqrt{2}}{40}
=-\frac{60\sqrt{2}}{40}
=-\frac{3\sqrt{2}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{2}}{2*20}=\frac{0+60\sqrt{2}}{40}
=\frac{60\sqrt{2}}{40}
=\frac{3\sqrt{2}}{2}
$